Reducing the field of view (FOV) by a factor of 2 will reduce the voxel volume by which factor?

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Reducing the field of view (FOV) by a factor of 2 effectively reduces each dimension of the FOV—length, width, and height—by that factor. Since voxel volume is calculated as the product of these three dimensions (Volume = Length × Width × Height), when each dimension is halved, the new volume can be calculated as follows:

If the original dimensions are halved (from L to L/2, W to W/2, and H to H/2), the new voxel volume becomes:

New Volume = (L/2) × (W/2) × (H/2) = (1/8) × (L × W × H)

This means the new volume is 1/8 of the original volume. Therefore, reducing the FOV by a factor of 2 results in reducing the voxel volume by a factor of 4 (which is the reciprocal of 1/8, since the original volume is now divided by 8).

As a result, choosing the value for the reduction of voxel volume confirms that the voxel volume is reduced by a factor of 4 when the FOV is reduced by a factor of 2. This principle is vital in MRI as it directly

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